The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $155,574 | $4,693 | $24,610 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $135,544 | $14,056 | $15,148 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $130,948 | $16,944 | $12 |