The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $138,575 | $12,548 | $24,597 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $120,682 | $15,047 | $2,888 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $139,359 | $3,553 | $9,862 |