The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $128,999 | $4,652 | $16,638 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $158,115 | $4,355 | $3,812 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $158,357 | $2,059 | $9,699 |