The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $160,265 | $6,866 | $5,039 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $161,288 | $12,026 | $15,871 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $157,808 | $14,496 | $12,082 |