The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $148,000 | $4,196 | $22,738 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $139,253 | $15,689 | $23,066 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $123,085 | $175 | $239 |