The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $141,913 | $7,914 | $6,266 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $134,941 | $13,890 | $16,716 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $166,612 | $12,069 | $15,240 |