The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $169,420 | $8,832 | $20,622 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $151,876 | $6,418 | $14,279 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $127,573 | $2,156 | $15,651 |