The average total compensation for the Rotational Development Program position at IBM is $52,000.
Compensation Percentile BreakdownSample Size: 9
10th
$183,80025th
$250,75050th
$260,00075th
$272,50090th
$301,100Recent Data Points
| Start Date | Company | Position | Salary | Bonus | Other |
|---|
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $160,990 | $10,820 | $2,302 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $162,370 | $7,446 | $20,359 |
| Aug, 2017 | McKinsey & Company, Inc. | Associate | $164,805 | $16,351 | $18,503 |